11.1

1.)

a) the wrapped penny was less corroded than the unwrapped penny

b) the protection cam from both the coating and sacrificial techniques because it was coated with steel wool and it was protected by the other penny.

c)  Copper isn't very reactive but iron can be oxidized but this prevents further oxidation because copper can't be oxidized.

2.)   These areas started to corrode because aluminum is higher on table J than iron

3.)    This could have been prevented if the spots were sealed with caulking because it uses the technique of "sacrifice"

4.)

a)  Corrosion is the breaking down of a metal and it is caused by the loss of valence electrons in an element over time.

b) A chemist can outsmart corrosion by coating the metal they need with another metal or the process of "sacrifice" 

11.2

1.)

a)  I think think this name is appropriate because it really doesn't do anything to help the reaction it just watches the other elements try to react.

b) Silver is oxidized and magnesium was reduced

2.)    They will react only if element y is higher on table j than table x

3.)

a.) An activity series is the ability of an element to lose electrons

b) This is able to predict that metals will be high on table j and non-metals will be low on table J

4.)

Gold and the other 4 elements were found pure because they aren't very reactive and if they don't react with anything they are found pure.

5.)   Copper and Tin were melted together to form bronze

10.2

Our graph was similar to the one on table G but, Our amount of solvent was 10% of the amount of solvent used in Table G. That affected or graph a lot because the values were totally different and there was less solute.

The temperature can have a huge impact on how quickly the KClO3 dissolved. Surface area can also affect how quickly something dissolves. When you raise the temperature the collisions of the molecules become a lot more effective. Surface area relates to how quick the KClO3 dissolves because the more space it takes up the longer it'll take to dissolve. Particle collisions make the KClO3 react which makes it dissolve and that's why it's important to the dissolving process.

Unsaturated:  When the KClO3 was undissovled at the bottom of the test tube

Saturated:      When the KClO3 is completely dissolved in the test tube

Supersaturated:  Never

10.1

In my experiment I discovered that sugar and salt were polar. The sample of vegetable oil was non-polar. From the data I collected I can say that ethanol's polarity was polar. Ethanol could dissolve in water since water is polar. Hexane would not dissolve in water because it is non-polar and water is polar. NH3 is a non-polar molecule and is would dissolve in hexane but not water. I2 is polar and it would dissolve in water but not hexane. HCl is polar and it would dissolve in water but not hexane. Ionic molecules dissolve in water because it is polar and their polarity is stronger compared to non-polar molecules.

9.2

  Station one:

When the HCl was added it shifted to the right because it added to the Cl-1 and that stressed the reaction on the products side of the equation 

1.) When the system was heated it shifted to the right and that means that the "heat energy" was on the products side of the equation

2.) If the potential energy of the products is more than the reactants then the heat of reaction will be positive and the reaction will be endothermic. If the potential energy of the products is less than the reactants that means that the heat of reaction will be negative and that means that the reaction is exothermic.


3.)
a)  Table F shows that the interaction between Ag 1+ and Cl 1- is insoluble

b) I know that when i added AgNO3 to the solution the reaction from table F occurred because the two elements mixed and there was no separation.

c) When AgNO3 was added the system shifted to the left because the reaction was trying to reach equilibrium by shifting back to the left when it was already shifted to the right.

Station 3 Processing Question

1.) When the bottle was opened the pressure shifts to the right side of the system and the system does that so that it can reach equilibrium.

9.1

My solution process was endothermic. I know this because the temperature of the solution was 14.4 degrees higher than the original temperature of the water. When the element was added to the water the heat transferred from the surroundings of the water into the water.

One thing that could cause different values is measurement. If you used too much or too little of a substance then it could have caused our values to vary. Another way would be that they used pure water in their calculations but the tap water has iron in it.

3.)  
a)  If the temperature of the room was 10 degrees colder there would be less moles of solute because the colder it is the slower the reaction happens

b) If you added less chemical but knew how much you added the moles of solute would be greater because there's less chemical but the reaction happens fast because there's less chemical to dissolve

c) If you added 40 mL of water but thought you added 50 mL you would have less moles of solute because there's less water for the chemical to be dissolved in

8.2

The higher the viscosity the stronger the intermolecular forces and the higher the boiling point the stronger the intermolecular forces. The smaller the molecule the stronger the intermolecular forces